Sunday, October 8, 2017

[LeetCode]Combinations


Backtrack的题目,没有什么好说的。时间复杂度O(C(n , k)),空间复杂度k,代码如下:


class Solution {
public:
vector<vector<int>> combine(int n, int k) {
if(k > n)return {};
vector<vector<int>> res;
vector<int> curr;
backtrack(res, curr, 1, n, k);
return res;
}
private:
void backtrack(vector<vector<int>>& res, vector<int>& curr, int i, int n, int k)
{
if(curr.size() == k)
{
res.push_back(curr);
return;
}
for(int j = i; j <= n; ++j)
{
curr.push_back(j);
backtrack(res, curr, j+ 1, n, k);
curr.pop_back();
}
}
};

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